What if you had ten toppings available. How many different two-topping pizza variations can you make ...

What definition did you have to "adjust" in order to get David's answer of 55?

Do you agree that this is a fair interpretation of the problem?

source:

```
10 pizza toppings
Choose any 2 - different or same;
How many choices?
```

10×9÷2=45?

10×10÷2=50?

10×11÷2=55?

10C1+10C2?

Ans: 55 Why?

— David Marain (@dmarain)

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