$\sqrt{x^2+y^2+z^2}=?$
Should we brute-force this or is there a more beautiful or subtle way of getting what we want?
Source:
(x+12)²+(y+4)²+(z+3)²=0
√(x²+y²+z²)=?
#SATPrep #mathchat #algebra
— David Marain (@dmarain) May 13, 2015
Wednesday, May 13, 2015
458: Is That You, Pythagoras?
If we stipulate that $(x+12)^2+(y+4)^2+(z+3)^2=0$, then
$\sqrt{x^2+y^2+z^2}=?$
Should we brute-force this or is there a more beautiful or subtle way of getting what we want?
Source:
$\sqrt{x^2+y^2+z^2}=?$
Should we brute-force this or is there a more beautiful or subtle way of getting what we want?
Source:
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