What if you had ten toppings available. How many different two-topping pizza variations can you make ...
What definition did you have to "adjust" in order to get David's answer of 55?
Do you agree that this is a fair interpretation of the problem?
source:
10 pizza toppings
Choose any 2 - different or same;
How many choices?
10×9÷2=45?
10×10÷2=50?
10×11÷2=55?
10C1+10C2?
Ans: 55 Why?
— David Marain (@dmarain)
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